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AMC12 2015a Test Paper
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Sample Question 4:

The sum of two positive numbers is 5 times their difference. What is the ratio of the larger number to the smaller?

(A) 54(B) 32(C) 95(D) 2(E) 52\textbf{(A)}\ \frac54 \qquad\textbf{(B)}\ \frac32 \qquad\textbf{(C)}\ \frac95 \qquad\textbf{(D)}\ 2 \qquad\textbf{(E)}\ \frac52




Answer Keys

Question 4: B


Solutions

Question 4
Step 1: Let's denote the larger number as aa and the smaller number as bb.

Step 2: According to the problem, the sum of these two numbers is 5 times their difference. Mathematically, this can be represented as a+b=5(ab)a + b = 5(a - b).

Step 3: Expanding the right side of the equation gives a+b=5a5ba + b = 5a - 5b.

Step 4: By rearranging the terms, we obtain 4a=6b4a = 6b.

Step 5: Factoring the equation results in 2a=3b2a = 3b.

Step 6: Solving for the ratio of aa to bb gives ab=32\frac{a}{b} = \frac{3}{2}.

So, the ratio of the larger number to the smaller number is 32\frac{3}{2}, which corresponds to answer choice (B) 32\textbf{(B)}\ \frac{3}{2}.