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AMC8 1997 Test Paper
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Sample Question 11:

Define \(\boxed{N}\) as the number of whole number divisors of \(N\). For example, \(\boxed{3}=2\) because 3 has two divisors, 1 and 3. Find the value of

\(\boxed{\boxed{11}\times\boxed{20}}.\)

\(\text{(A)}\ 6 \qquad \text{(B)}\ 8 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 16 \qquad \text{(E)}\ 24\)




Answer Keys

Question 11: A


Solutions

Question 11
Step 1: Compute \(\boxed{11}\) and \(\boxed{20}\). The number 11 has 2 whole number divisors (1 and 11) and the number 20 has 6 whole number divisors (1, 2, 4, 5, 10, 20).

Step 2: Multiply the numbers obtained from the first step, giving us \(2 \times 6 = 12\).

Step 3: Apply the \(\boxed{ \quad }\) function again to the result from the second step. Since the number 12 has 6 whole number divisors (1, 2, 3, 4, 6, 12), the final answer is 6, and we choose \(\boxed{\text{(A) }6}\).