Projectiles launced horizontally
The key for the analysis is to break the motion into the vertical component and horizontal component.
?y = viyt + 1/2 ayt2 = 1/2 gt2, because viy=0 and ay = g
?x = vixt + 1/2 axt2 = vixt, because ax = 0
Projectiles launced at an angle
The key for the analysis is to break the motion into the vertical component and horizontal component.
vix = v cos? and viy = v sin?
Vy = viy + at
viy - gtup = 0
tup = viy/g
?y = viyt + 1/2 at2
?ymax = viytup - 1/2 g(tup)2 = 1/2 (viy2/g)
Uniform circular motion
The direction of the acceleration (the centripetal acceleration) is toward the center of the circule and its magnitude is ac = v2 / r, where v is velocity and r is radius of the circle.
For uniform circular motion: magnitude of velocity v = 2?r / T, where r is radius and T is period (in seconds).
Period T = 1/f, where f is frequency.
ac = 4?2r / T2, where r is radius and T is period.
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